Arithmetic Series
Reference > Mathematics > Algebra > Sequences and SeriesA series is a little bit different from a sequence: a sequence is nothing more than an ordered list of numbers; a series is that same list combined with the addition operation.
For example, {1, 2, 3, 4} is an arithmetic sequence, and the arithmetic series that goes with this sequence is:
1 + 2 + 3 + 4. We say that the sum of the series, then, is 10.
A story is told about the mathematician Carl Frederick Gauss, who as a student was told to add all the integers from 1 to 100. Without wasting any time, he simply wrote down the answer 5050. When his teacher demanded to know how he got the answer so quickly, he explained as follows:
If you group them in pairs, from opposite ends of the series, you get 1 + 100, 2 + 99, 3 + 98, and so on.
Each of those pairs adds to 101, and there are 50 such pairs, so the sum is 101 x 50 = 5050.
The reasoning is correct, and leads us to the following formula, in which sn represents the sum of the first n terms:
sn = n/2(a1 + an)
Of course, we could write an = a1 + (n - 1)d, so that helps us out if we know the first term and the common difference.
I like putting formulas into words, because it helps me remember them, so I say that the sum of the series is the average of the first and last term, divided by the number of terms.
Example: If the first term is 5, and the common difference is 2, what is the sum of the first 10 terms?
Answer: a10 = 5 + 9 x 2 = 23.
Averaging the first and tenth terms gives us (5 + 23)/2 = 14. Multiplying this by the number of terms (10) gives us a sum of 140.
Example: If the first term is 3, and the common difference is 4, what is the sum of the third through 10th terms?
Answer: The third term is 3 + 4 x 2 = 11, and the tenth term is 3 + 4 x 9 = 39. The average is (11 + 39)/2 = 25. However, since we are starting with the 3rd term, we have a total of 8 terms, so the total is 25 x 8 = 200.
Example: If the first term is 5, and the second term is 3, find the sum of the first 20 terms.
Answer: The common difference in this case is -2. So the 20th term is 5 - 19 x 2 = -33. The average of the first and 20th terms is -14. There are twenty terms, so the sum is -14 x 20 = -280.
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