Geometric Series
Reference > Mathematics > Algebra > Sequences and SeriesJust as the terms of an arithmetic sequence can be added together to make an arithmetic series, the terms of a geometric sequence can also be added, forming a geometric series. Here's a simple example. If there is a geometric sequence as follows: 5, 10, 20, 40, 80, then we can write the sum of the geometric series this way: 5 + 10 + 20 + 40 + 80 = 155.
Of course, if the sequence had 50 terms, adding them up manually - even with a calculator - would be tedious. So let's see if we can work out a formula that'll help us find that sum.
Let's begin with a sequence in which the first term is a1, and the common ratio is r. Can we find the sum of the first n terms of the series?
Let's call Sn the sum of the first n terms. Then we can write:
Sn = a1 + a1r + a1r2 + ... + a1rn-1
Now, what I'm going to suggest that we do next might seem a little strange, but bear with me: Let's take that entire ugly equation and multiply both sides by r. You'll see why in a minute. For now, we're going to have:
Snr = a1r + a1r2 + a1r3 + ... + a1rn
Here's where things get really interesting: if we subtract the first equation from the second equation, a whole bunch of stuff cancels out! We end up with:
Snr - Sn=a1rn - a1
Now if you factor Sn on the left and factor out a1 on the right, and then divide both sides by (r - 1), you end up with:
Sn = a1(1 - rn )/(1 - r)
That formula is the basis for finding sums of geometric series, since it only involves a1, r, and n!
Example 1: Find the sum of the first 5 terms of a series in which the first term is 2, and the second term is 4.
Solution 1: The common ratio is 2. Thus, the sum is 2(1-25)/(1 - 2) = 62
Example 2: If the third term is 36, and the fourth term is 108, what is the sum of the first four terms?
Solution 2: r = 3, so the first term must be 4. n = 4, so plug these into the formula to obtain 157.
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