Rationalizing the Denominator - Part Two
Reference > Mathematics > Algebra > Simplifying Radicals
Everything you've learned about rationalizing the denominator goes out the window if the denominator of your fraction has a binomial in it. For example, if the denominator is 3 +
2, you might be tempted, based on what you know, to multiply the numerator and denominator by
2; after all, that's the radical in the denominator, right?
But look what happens if you multiply 3 +
2 by
2:
2(3 +
2) =
3
2 +
22 =
3
2 + 4
That's still not rationalized. You could keep multiplying by
2 over and over again, but it would never become rationalized.
2) by (3 -
2), then we'll end up with 32 -
22, which is 9 - 2, or 7. And presto! Our radical is gone!
So let's try an example of this: Simplify .
To rationalize the denominator, we need to multiply the numerator and denominator by (5 +
3).
= · = = =
Of course, the problem will be slightly more challenging if there's also a binomial in the numerator: Simplify .
Since the denominator is (2 -
2), we can simplify by multiplying the numerator and denominator by (2 +
2).
= · = = = 3 + 2
2






3


3


So what do we do?
Well, we need to remember one of our nice rules for factoring/multiplying binomials. It's the difference of squares rule, and it looks like this:
(a + b)(a - b) = a2 - b2
Why does that help us? Well, if we multiply (3 +


2
5 -
3


2
5 -
3

2
5 -
3

5 +
3

5 +
3

2(5 +
3)

25 - 3
2(5 +
3)

22
5 +
3

11
2 +
2

2 -
2



2 +
2

2 -
2

2 +
2

2 -
2

2 +
2

2 +
2

(2 +
2)2

4 - 2
6 + 4
2

2

Questions
1.
Simplify
2
3 +
2

2.
Simplify
1
5 -
3

3.
Simplify
5

5 -
5

4.
Simplify
3 +
2
1


5.
Simplify
3 -
2
3 +
2




6.
Simplify
1 +
2

1 +
3

7.
Simplify
2
3 -
x

8.
Simplify +
1
3 +
2

1
3 -
2


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